{"id":19649,"date":"2025-02-06T18:58:11","date_gmt":"2025-02-06T13:28:11","guid":{"rendered":"https:\/\/studybizz.com\/jobs\/?p=19649"},"modified":"2025-02-06T18:58:14","modified_gmt":"2025-02-06T13:28:14","slug":"csir-iict-junior-secretariat-assistant-recruitment-2025","status":"publish","type":"post","link":"https:\/\/studybizz.com\/jobs\/csir-iict-junior-secretariat-assistant-recruitment-2025\/","title":{"rendered":"CSIR IICT Junior Secretariat Assistant Recruitment 2025 Notification Out for 15 Vacancies"},"content":{"rendered":"\n

CSIR IICT Junior Secretariat Assistant Recruitment 2025:\u00a0<\/strong>The Indian Institute of Chemical Technology has released the official notification for the recruitment of Junior Secretariat Assistant posts. The total number of posts for CSIR IICT Recruitment 2025 is 15. The CSIR IICT Recruitment 2025 Notification has been released on 30 January 2025 and the Online Application will be accepted from 31 January 2025 to 3 March 2025.<\/p>\n\n\n\n

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Table of Contents<\/p>\nToggle<\/span>
CSIR IICT Junior Secretariat Assistant Recruitment 2025 Overview<\/a><\/li>
Important Dates<\/a><\/li>
Application Fee<\/a><\/li>
Vacancy, Qualification<\/a><\/li>
Selection Process<\/a><\/li>
Important Links<\/a><\/li><\/ul><\/nav><\/div>\n
<\/span>CSIR IICT Junior Secretariat Assistant Recruitment 2025 Overview<\/span><\/h2>\n\n\n\n
Recruitment Organization<\/td> Indian Institute of Chemical Technology<\/td><\/tr>
Post Name<\/td> Junior Secretariat Assistant<\/td><\/tr>
Advt. No.<\/td> 02\/2025<\/td><\/tr>
Total Vacancies<\/td> 15<\/td><\/tr>
Notification Date<\/td> 31 January 2025<\/td><\/tr>
Post Category<\/td> CSIR IICT Junior Secretariat Assistant Recruitment 2025<\/td><\/tr>
Official Website<\/td> iict.res.in<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
<\/span>Important Dates<\/span><\/h2>\n\n\n\n
Apply Start Date<\/td> 31 January 2025<\/td><\/tr>
Apply Last Date<\/td> 03 March 2025<\/td><\/tr>
Exam Date<\/td> Notify Later<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
<\/span>Application Fee<\/span><\/h2>\n\n\n\n
General\/ OBC\/ EWS<\/td> Rs. 500\/-<\/td><\/tr>
SC\/ ST\/ PWD\/Female\/ESM<\/td> Rs. 0\/-<\/td><\/tr>
Mode of Payment<\/td> Online<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
<\/span>Vacancy, Qualification<\/span><\/h2>\n\n\n\n
Age Limit<\/strong>: 18-28 Years. (As on 03.03.2025)<\/td><\/tr>
Post Name<\/strong><\/td> Vacancy<\/strong><\/td> Qualification<\/strong><\/td><\/tr>
Junior Secretariat Assistant<\/td> 15<\/td> 12th Pass + Typing<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
<\/span>Selection Process<\/span><\/h2>\n\n\n\n
1. Written Exam (Time: 2 Hours 30 Minutes, Negative Marking Paper II:- Yes)
2. Typing Test
3. Document Verification
4. Medical Examination<\/p>\n\n\n\n
Subject<\/strong><\/td> Questions<\/strong><\/td> Marks<\/strong><\/td><\/tr>
Mental Ability Test (Paper-1)<\/td> 100<\/td> 200<\/td><\/tr>
English (Paper-2)<\/td> 50<\/td> 150<\/td><\/tr>
GK (Paper-2)<\/td> 50<\/td> 150<\/td><\/tr>
Total<\/strong><\/td> 200<\/strong><\/td> 500<\/strong><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
<\/span>Important Links<\/span><\/h2>\n\n\n\n
CSIR IICT Junior Secretariat Assistant Recruitment 2025\u00a0Notification PDF<\/strong><\/td> Notification<\/a><\/strong><\/td><\/tr>
CSIR IICT Junior Secretariat Assistant Recruitment 2025\u00a0Apply Online<\/strong><\/td> Online Form<\/a><\/strong><\/td><\/tr>
CSIR IICT\u00a0Official Website<\/strong><\/td> CSIR IICT<\/a><\/strong><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
<\/p>\n<\/body>","protected":false},"excerpt":{"rendered":"
CSIR IICT Junior Secretariat Assistant Recruitment 2025:\u00a0The Indian Institute of Chemical Technology has released the official notification for the recruitment of Junior Secretariat […]<\/p>\n","protected":false},"author":1,"featured_media":19651,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[7],"tags":[],"class_list":["post-19649","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-job-notifications"],"_links":{"self":[{"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/posts\/19649","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/comments?post=19649"}],"version-history":[{"count":1,"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/posts\/19649\/revisions"}],"predecessor-version":[{"id":19652,"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/posts\/19649\/revisions\/19652"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/media\/19651"}],"wp:attachment":[{"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/media?parent=19649"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/categories?post=19649"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/studybizz.com\/jobs\/wp-json\/wp\/v2\/tags?post=19649"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}